# Problem 863 | Deflection by Three-Moment Equation

**Problem 863**

For the beam shown in Fig. P-863, determine the value of EIδ midway between the supports and at the left end.

**Answer**

$\delta = \dfrac{1066.67}{EI} ~ \text{ upward}$

At the left end

$\delta = \dfrac{16,000}{EI} ~ \text{ downward}$

For the complete solution using the three moment equation, see it here: http://www.mathalino.com/reviewer/strength-materials/problem-863-deflect...

# Problem 862 | Deflection by Three-Moment Equation

# Problem 861 | Deflection by Three-Moment Equation

# Problem 860 | Deflection by Three-Moment Equation

# The Polar Coordinate System

In Polar Coordinate System, the references are a fixed point and a fixed line. The fixed point is called the **pole** and the fixed line is called the **polar axis**. The location of a point is expressed according to its distance from the pole and its angle from the polar axis. The distance is denoted by r and the angle by θ.

# 02 Location of the third point on the parabola for largest triangle

# Area for grazing by the goat tied to a silo

# Perimeter of the curve r = 4(1 + sin theta) by integration

# Length of Arc in Polar Plane | Applications of Integration

The length of arc on polar plane is given by the formula:

The formula above is derived in two ways. See it here: http://www.mathalino.com/reviewer/integral-calculus/length-arc-polar-pla...