# Second Shifting Property | Laplace Transform

**Second Shifting Property**

If $\mathcal{L} \left\{ f(t) \right\} = F(s)$, and $g(t) = \begin{cases}{f(t - a) & t > a \\ 0 & t

then,

**Second Shifting Property**

If $\mathcal{L} \left\{ f(t) \right\} = F(s)$, and $g(t) = \begin{cases}{f(t - a) & t > a \\ 0 & t

then,

$\mathcal{L} \left\{ g(t) \right\} = e^{-as} F(s)$

**Problem 361**

Referring to Problem 359, if T = 30 kN and x = 1 m, determine the angle θ at which the bar will be inclined to the horizontal when it is in a position of equilibrium.

**Problem 360**

Referring to Problem 359, what value of T acting at x = 1 m from B will keep the bar horizontal.

**Problem 359**

A 4-m bar of negligible weight rests in a horizontal position on the smooth planes shown in Fig. P-359. Compute the distance x at which load T = 10 kN should be placed from point B to keep the bar horizontal.

**Problem 358**

A bar AE is in equilibrium under the action of the five forces shown in Fig. P-358. Determine P, R, and T.

**Problem 357**

The uniform rod in Fig. P-357 weighs 420 lb and has its center of gravity at G. Determine the tension in the cable and the reactions at the smooth surfaces at A and B.

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