February 2017

Problem 878 | Continuous Beam by Moment Distribution Method

Problem 878
Using moment-distribution method, solve for the moments over supports R₂ and R₃ of the continuous beam in Figure P-826.

Problem 879 | Continuous Beam by Moment Distribution Method

Problem 879
Using moment-distribution method, solve for the moments over supports R₂ and R₃ of the continuous beam in Figure P-827.

Problem 880 | Continuous Beam by Moment Distribution Method

Problem 880
Compute the moments over the supports of the beam shown in Fig. P-845.

Problem 881 | Continuous Beam by Moment Distribution Method

Problem 881
Compute the moments over the supports of the beam shown in Fig. P-846.

Problem 882 | Continuous Beam by Moment Distribution Method

Problem 882
Compute the moments over the supports of the beam shown in Fig. P-849.

Differential equation. how to solve?

Submitted by Nelvie Cambay M... on February 5, 2017 - 11:56pm

1. (x^2 + 2xy - 4y^2) dx - ( x^2 - 8xy - 4 y^2)dy=0
2. y(9x-2y)dx-x(6x-y)dy=0; when: x=1; y=1/2

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Problem 883 | Continuous Beam by Moment Distribution Method

Problem 883
Compute the moments over the supports of the beam shown in Fig. P-853.

Problem 884 | Continuous Beam by Moment Distribution Method

Problem 884
Compute the moments over the supports of the beam shown in Fig. P-856.

Problem 885 | Continuous Beam by Moment Distribution Method

Problem 885
Solve for the support moments in Problem 825 if the ends are perfectly fixed instead of simply supported.

Grabber - statics example

Submitted by 0183963506 on February 11, 2017 - 8:00pm

Hello,

We should get the length x , when the grabber can just hold the box.

grabber

I made two moment equations:

Then I put them together into one equation: m1m2

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Bernoulli's differential equation

Submitted by Horlamide Luqman on February 13, 2017 - 12:56am

Hello ,please someone should help with out with these Diffrential equations
a. xdy + ydx = x^3 y^6 dx
b. cosysin2xdx +(cos^2y - cos^x)dy = 0

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Most often, a structural member is subjected to different types of stresses that acts simultaneously. Such stresses are axial, shear, flexure, and torsion. Superposition method is used to determine the combined effect of two or more stresses acting over the cross-section of the member.

Axial stress
$$\sigma = \pm\dfrac{P}{A}$$

Shear stress
$$\tau = \dfrac{VQ}{Ib}$$

Flexural stress
$$\sigma_f = \dfrac{Mc}{I}$$

Torsional stress
$$\tau = \dfrac{T\rho}{J}$$

Combined Axial and Bending

Problem 902
Compare the maximum stress in bent rod 1/2 in. square, where the load P is 1/2 in. off center as shown in Figure P-902, with the maximum stress if the rod were straight and the load applied axially.

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Problem 903 | Combined Axial and Bending

Problem 903
A cast iron link is 40 mm wide by 200 mm high by 500 mm long. The allowable stresses are 40 MPa in tension and 80 MPa in compression. Compute the largest compressive load P that can be applied to the ends of the link along a longitudinal axis that is located 150 mm above the bottom of the link.

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Colored beads

Submitted by Alexander on February 15, 2017 - 6:26am

there were 198 blue beads in Box A and 219 Pink beads in Box B. some green beads were added to Box A and some yellow beads were added to Box B. for every 3 blue beads in Box A, 13 green once were added to Box A as s result, Box A had 4 times as many beads as Box B. how many yellow beads were added to Box B?

two straight line are perpendicular to each other an observer is on one road and 180m

Submitted by Liezel Tuliao B... on February 18, 2017 - 1:25am

two straight line are perpendicular to each other an observer is on one road and 180m. from the.intersection of two roads.the line of sight from the observer to two points A and B.

Strength of Materials (Stresses in a truss)

Submitted by Jal Rhee Ducusi... on February 18, 2017 - 6:09pm

Mga idol. Pwede pa turo pano to? Thanks in advance.

Problem 1

For a truss loaded as show, choose the lightest 2-angle sections to safely carry the maximum stress. The yielding stress of steel is 240 MPa. Use allowable compressive stress of 0.45 of the yielding stress and allowable tensile stress of 0.60 of the yielding stress. Assume that provision for buckling is provided.
F1 = 15 KN; F2 = 14 KN

Bolt Calculation

Submitted by Ismayil Bashirli on February 18, 2017 - 8:23pm

Can you help me to solve bolt calculate? how can I find document and exercises? Please help me.

Problem 904 | Combined Axial and Bending

Problem 904
To avoid interference, a link in a machine is designed so that its cross-sectional area is reduced one half at section A-B as shown in Fig. P-904. If the thickness of the link is 50 mm, compute the maximum force P that can be applied if the maximum normal stress on section A-B is limited to 80 MPa.

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Problem 905 | Combined Axial and Bending

Problem 905
A wooden beam 100 mm by 200 mm, supported as shown in Figure P-905, carries a load P. What is the largest safe value of P is the maximum stress is not to exceed 10 MPa?

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