Problem A tensile load of 8000 kg elongates a 1-m long square rod by 1 mm. Steel modulus of elasticity is 2 × 106 kg/cm2. What is the dimension of a side of the rod?
Answer Key
Solution
$0.1 = \dfrac{8,000(100)}{x^2 (2 \times 10^6)}$
$x^2 = 4$
$x = 2 ~ \text{cm}$ ← Answer: [ C ]
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