## Subject:

**Problem**

A tensile load of 8000 kg elongates a 1-m long square rod by 1 mm. Steel modulus of elasticity is 2 × 10^{6} kg/cm^{2}. What is the dimension of a side of the rod?

A. 5 cm | C. 2 cm |

B. 1 cm | D. 4 cm |

**Answer Key**

[ C ]

**Solution**

$\delta = \dfrac{PL}{AE}$

$0.1 = \dfrac{8,000(100)}{x^2 (2 \times 10^6)}$

$x^2 = 4$

$x = 2 ~ \text{cm}$ ← Answer: [ C ]