Hello,
We should get the length x , when the grabber can just hold the box.
I made two moment equations:
Then I put them together into one equation: 
And from that equation I found out x: 
Unfortunately the result seems to be wrong. Can you please help me? Where I made the mistake?
$\Sigma M_H = 0$
$(x\sin \alpha)(\frac{1}{2}G) + \frac{1}{2}G(\frac{1}{2}b) = \dfrac{G}{2\mu_0}(l_1 + l_2)$
$x = \dfrac{2(l_1 + l_2) - \mu_0 b}{2\mu_0 \sin \alpha}$
Thank you very much sir!
It is the right solution and now when I have understood it, it looks so much simplier than before.
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