By inspection, the graph cannot exist at quadrants where x and y are negative because when x is negative x3/2 is imaginary, the same true to y. We can therefore see that the graph will only lie on the 1st quadrant
Try point plotting and rewrite the equation into y = (8 - x1.5)2/3
x
0
1
2
3
4
y
4
3.66
2.99
1.99
0
For finer graph, you may increment by 0.5 instead of by 1. Hint: If you are using a calculator with table capability you can tabulate the data above. For CASIO fx-991ES use MODE7:TABLE
By inspection, the graph cannot exist at quadrants where x and y are negative because when x is negative x3/2 is imaginary, the same true to y. We can therefore see that the graph will only lie on the 1st quadrant
Try point plotting and rewrite the equation into y = (8 - x1.5)2/3
For finer graph, you may increment by 0.5 instead of by 1. Hint: If you are using a calculator with table capability you can tabulate the data above. For CASIO fx-991ES use
MODE
7:TABLE
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