Differential Equations

Find the differential equations of the following family of curves.

1. Parabolas with axis parallel to the y – axis with distance vertex to focus fixed as a.

2. Parabolas with axis parallel to the x – axis with distance vertex to focus fixed as a.

3. All ellipses with center at the origin and axes on the coordinate axes.

4. Family of cardioids.

5. Family of 3 – leaf roses.

1

(1) Upwards and downwards parabolas with latus rectum equal to 4a.

$y - k = \pm 4a(x - h)^2$

$y' = \pm 8a(x - h)$

$y'' = \pm 8a$

y−k=±4a

_{(x−h)}2 is this the equation for parabolas?isn't it 4a(y-k)=

_{(x-h)}2 ?I made a mistake in there, it should be (

x-h)^{2}= ±4a(y-k). The solution for (1) should go this way:$(x - h)^2 = \pm 4a(y - k)$

$2(x - h) = \pm 4ay'$

$2 = \pm 4ay''$

$y'' = \pm \frac{1}{2a}$

y−k=±4a

_{(x−h)}2 is this the equation for parabolas?isn't it 4a(y-k)=

_{(x-h)}2 ?Yes you are right, please refer to my reply above

so for number 2,

_{x-h=±4a(y-k)}2x'=±8a(y-k)

x''=±8a

am i wrong?

It is better to express your answer in terms of

y'rather thanx'. Althoughx'will do and simpler.$(y − k)^2 = \pm 4a(x − h)$

$2(y − k)y' = \pm 4a$

$y' = \dfrac{\pm 2a}{y - k}$

$y'' = \dfrac{\mp 2a \, y'}{(y - k)^2}$

$y'' = \dfrac{\mp 2a \, y'}{\left( \dfrac{y'}{\pm 2a} \right)^2}$

$y'' = \dfrac{\mp 8a}{y'}$

$y'' \, y' = \pm 8a$

Thank You so much sir.

sir, do you know the standard or general equations for the last 3 problems?

what equations should i use?

I think you are from ADZU haha