A student club on a college charges monthly membership dues of P10, less 5 centavos for each member over 60. How many members would give the club, the most revenue from the monthly dues?
Let R = monthly revenue x = number of student-member in excess of 60 x + 60 = total number of student-member
For number of members ≤ 60 monthly dues for each member = P10
For number of members > 60 monthly dues for each member = P(10 - 0.05x)
$R = 600 + 7x - 0.05x^2$
$\dfrac{dR}{dx} = 7 - 0.1x = 0$
$x = 70$
total number of members = 70 + 60 = 130 answer
thank you kaayu sir.
way sapayan
More information about text formats
Follow @iMATHalino
MATHalino
Let
R = monthly revenue
x = number of student-member in excess of 60
x + 60 = total number of student-member
For number of members ≤ 60
monthly dues for each member = P10
For number of members > 60
monthly dues for each member = P(10 - 0.05x)
$R = 600 + 7x - 0.05x^2$
$\dfrac{dR}{dx} = 7 - 0.1x = 0$
$x = 70$
total number of members = 70 + 60 = 130 answer
thank you kaayu sir.
way sapayan
Add new comment