1. (x^2 + 2xy - 4y^2) dx - ( x^2 - 8xy - 4 y^2)dy=0

2. y(9x-2y)dx-x(6x-y)dy=0; when: x=1; y=1/2

February 5, 2017 - 11:56pm

#1
Differential equation. how to solve?

SPONSORED LINKS

- ELLIPSE PERIMETER
- virtual work method
- Right triangle problem
- Integral calculus:Application
- Inverse Matrix
- Area of Arrow Polygon
- What temperature is twice as cold as zero degree Celsius
- Process Control
- inverse laplace transform of (5s^2 - 15s - 11) / [ (s + 1)(s - 3)^3 ]
- A sample of dry sand is subjected to a tri-axial test

both equation are homogeneous. You can use either of the following substitution:

dy = v dx + x dv

dx = v dy + y dv

The result would be separable equation which you can easily solve. And don't forget to revert back to original variables of x and y then apply boundary conditions as necessary.

thank you po. ☺