Following is a discussion on the Reviewer item titled: Problem 512 | Friction.
Feel free to add your own comments!
Home • Forums • Blogs • Glossary • Recent
About • Contact us • Terms of Use • Privacy Policy • Hosted by Linode • Powered by Drupal
About • Contact us • Terms of Use • Privacy Policy • Hosted by Linode • Powered by Drupal
Forum posts (unless otherwise specified) licensed under a Creative Commons Licence.All trademarks and copyrights on this page are owned by their respective owners. Forum posts are owned by the individual posters.
please tell me ,how we got this ph=40(w sin x)+20(w cos x)
The equation you mentioned is the moment about point A.
W sin (theta) = x-component of W or Wx and
W cos (theta) = y-component of W or Wy.
IT'S VARIGNON'S THEOREM AS IT STATES MOMENT SUM ABOUT ANY PT. =SUM OF ALL MOMENTS DUE TO ALL FORCES =>FORCE*DIST = MOMENT
then why dont u take w cos [theta] multiply with perpendicular distance to get moment about A
if y- component is wcos[thetA] then whAt About normAl reAction
Analyze the forces involved when the block starts to tip over point A and you will find it why.
Add new comment