From FBD for Support Reactions
$\Sigma M_E = 0$
$2A_H = 2(12)$
$A_H = 12 ~ \text{kN}$ answer
$\Sigma F_H = 0$
$E_H = A_H$
$E_H = 12 ~ \text{kN}$ answer
$\Sigma F_V = 0$
$E_V + A_V = 12$ †
From the FBD of Member AB
$\Sigma F_V = 0$
By Symmetry
$A_V = B_V = \frac{1}{2}(12)$
$A_V = B_V = 6 ~ \text{kN}$ answer
Substitute AV = 6 kN to †
$E_V + 6 = 12$
$E_V = 6 ~ \text{kN}$ answer
From FBD for Section Below M-M
$\Sigma M_D = 0$
$1.5F_{BC} = 2.5(6)$
$F_{BC} = 10 ~ \text{kN tension}$ answer
$\Sigma F_H = 0$
$\frac{3}{5}F_{BD} = 12$
$F_{BD} = 20 ~ \text{kN compression}$ answer