From Member CD
$\Sigma M_D = 0$
$60C_V = 30(12) + 20(6)$
$C_V = 8\text{t}$
$\Sigma M_C = 0$
$60D_V = 30(12) + 40(6)$
$D_V = 10\text{t}$
From the Section to the Left of C
$\Sigma M_B = 0$
$50R_A + 20(8) = 20(20)$
$R_A = 4.8\text{t}$ answer
$\Sigma M_A = 0$
$50R_B = 30(20) + 70(8)$
$R_B = 23.2\text{t}$ answer
From the Section to the Right of D
$\Sigma M_F = 0$
$50R_E = 30(20) + 70(10)$
$R_E = 26\text{t}$ answer
$\Sigma M_E = 0$
$50R_F + 20(10) = 20(20)$
$R_F = 4\text{t}$ answer