Solution to Problem 586 | Design for Flexure and Shear

Problem 586
The distributed load shown in Fig. P-586 is supported by a box beam having the same cross-section as that in Prob. 585. Determine the maximum value of wo that will not exceed a flexural stress of 10 MPa or a shearing stress of 1.0 MPa.
 

Solution to Problem 585 | Design for Flexure and Shear

Problem 585
A simply supported beam of length L carries a uniformly distributed load of 6000 N/m and has the cross section shown in Fig. P-585. Find L to cause a maximum flexural stress of 16 MPa. What maximum shearing stress is then developed?
 

Solution to Problem 584 | Design for Flexure and Shear

Problem 584
A wide-flange section having the dimensions shown in Fig. P-584 supports a distributed load of wo lb/ft on a simple span of length L ft. Determine the ratio of the maximum flexural stress to the maximum shear stress.
 

Solution to Problem 583 | Design for Flexure and Shear

Problem 583
A rectangular beam 6 in. wide by 10 in. high supports a total distributed load of W and a concentrated load of 2W applied as shown in Fig. P-583. If fb ≤ 1500 psi and fv ≤ 120 psi, determine the maximum value of W.
 

Solution to Problem 582 | Design for Flexure and Shear

Problem 582
Find the cross-sectional dimensions of the smallest square beam that can be loaded as shown in Fig. P-582 if fv ≤ 1.0 MPa and fb ≤ 8 MPa.
 

Solution to Problem 581 | Design for Flexure and Shear

Problem 581
A laminated beam is composed of five planks, each 6 in. by 2 in., glued together to form a section 6 in. wide by 10 in. high. The allowable shear stress in the glue is 90 psi, the allowable shear stress in the wood is 120 psi, and the allowable flexural stress in the wood is 1200 psi. Determine the maximum uniformly distributed load that can be carried by the beam on a 6-ft simple span.
 

Solution to Problem 580 | Design for Flexure and Shear

Problem 580
A rectangular beam of width b and height h carries a central concentrated load P on a simply supported span of length L. Express the maximum fv in terms of maximum fb.
 

Design for Flexure and Shear

To determine the load capacity or the size of beam section, it must satisfy the allowable stresses in both flexure (bending) and shear. Shearing stress usually governs in the design of short beams that are heavily loaded, while flexure is usually the governing stress for long beams. In material comparison, timber is low in shear strength than that of steel.
 

Solution to Problem 577 | Horizontal Shearing Stress

Problem 577
A plywood beam is built up of 1/4-in. strips separated by blocks as shown in Fig. P-577. What shearing force V will cause a maximum shearing stress of 200 psi?
 

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