02 - Problems involving sum of two numbers

Problem 3
A man bought a cellphone and laptop for P50,000.00, paying three times as much for the laptop as for the cellphone. How much did each cost?
 

Problem 4
Two boys, counting their money, found that together they had P372, and that Rody had five times as much as Mar. How much had each?
 

01 - Problems involving sum of two numbers

Problem 1
The sum of two numbers is 120. If the greater number is four times the less, what are the numbers?
 

Problem 2
The greater of two numbers is twice the less, and the sum of the numbers is 96. What are the numbers?
 

Equation of a curve with given equation of slope and passing through a point

Problem
What is the equation of the curve passing through the point (3, -2) and having a slope at any point (x, y) equal to (x2 + y2) / (y3 - 2xy)?
 

03 Point P Inside an Isosceles Right Triangle

Problem
Point P is inside the isosceles right triangle ABC. AP is 15 cm, BP is 9 cm and CP is 12 cm as shown. Determine the area of the triangle ABC.
 

034-point-p-inside-isosceles-right-triangle.gif

 

Problem 604 | Resultant of Concurrent Forces in Space

Problem 604
604-resultant-3d-forces.gifDetermine the magnitude of the resultant, its pointing, and its direction cosines for the following system of non-coplanar concurrent forces. 200 lb (4, 5, –3); 400 lb (–6, 4, –5); 300 lb, (4, –2, –3).
 

Problem 603 | Resultant of Concurrent Forces in Space

Problem 603
603-resultant-3d-forces.gifDetermine the magnitude of the resultant, its pointing, and its direction cosines for the following system of non-coplanar concurrent forces. 100 lb (2, 3, 4); 300 lb (–3, –4, 5); 200 lb, (0, 0, 4).
 

Problem 602 | Resultant of Concurrent Forces in Space

Problem 602
Determine the magnitude of the resultant, its pointing and its direction cosines for the following system of non-coplanar, concurrent forces. 300 lb (+3, -4, +6); 400 lb (-2, +4, -5); 200 lb (-4, +5, -3).
 

602-resultant-3d-forces.gif

 

Problem 864 | Deflection by Three-Moment Equation

Problem 864
An 18-ft beam, simply supported at 4 ft from each end, carries a uniformly distributed load of 200 lb/ft over its entire length. Compute the value of EIδ at the middle and at the ends.
 

864-overhanging-simple-bem.gif

 

Problem 863 | Deflection by Three-Moment Equation

Problem 863
For the beam shown in Fig. P-863, determine the value of EIδ midway between the supports and at the left end.
 

863-verhang-beam-given.gif

 

Answer

At midway between the supports
$\delta = \dfrac{1066.67}{EI} ~ \text{ upward}$
 

At the left end
$\delta = \dfrac{16,000}{EI} ~ \text{ downward}$

 

For the complete solution using the three moment equation, see it here: http://www.mathalino.com/reviewer/strength-materials/problem-863-deflect...
 

Problem 862 | Deflection by Three-Moment Equation

Problem 862
Determine the value of EIδ at B for the beam shown in Fig. P-862.
 

862-simple-beam-given.gif

 

Pages

Subscribe to MATHalino RSS