Problem 01 Find the Laplace transform of $f(t) = e^{2t}t^3$.
Solution 01
$\mathcal{L}(t^3) = \dfrac{3!}{s^{3 + 1}}$
$\mathcal{L}(t^3) = \dfrac{6}{s^4}$
Thus, $\mathcal{L}(e^{2t}t^3) = \dfrac{6}{(s - 2)^4}$ answer
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