
Let

= ∠HCO = ∠ECO

From right triangle BFC



From right triangle CEO




Area of trapezoid BCEG

![$ A_{BCEG} = 10 \left[ \dfrac{15}{\tan \theta} + \left( \dfrac{15}{\tan \theta} - \dfrac{20}{\tan 2\theta} \right) \right] $](/files/tex/b0f466b9cd0c62583b039bd8018ec6639c7c4761.png)

Area of trapezoid ABCD



For maximum area, dA/dθ = 0:










From right triangle BFC


answer
A solution to the same problem has been done by Geometry without the use of Calculus. In that solution, the location of the tangent point H has been pointed out by direct analogy. See how it was done by following this link: Solution by Geometry alone
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