Problem 02 $y \sin x - xy^2 = c$
Solution 02
$(y \cos x~dx + \sin x~dy) - (2xy~dy + y^2~dx) = 0$
$y \cos x~dx + \sin x~dy - 2xy~dy - y^2~dx = 0$
$(y \cos x~dx - y^2~dx) + (\sin x~dy - 2xy~dy) = 0$
$y(\cos x - y)~dx + (\sin x - 2xy)~dy = 0$ answer
Follow @iMATHalino
MATHalino