$\theta = 20^\circ + 30^\circ$
$\theta = 50^\circ$
Perpendicular component
$P_n = 1800 \tan \theta = 1800 \tan 50^\circ$
$P_n = 2145.16 \, \text{ N}$ answer
Value of P
$P = \dfrac{1800}{\cos \theta} = \dfrac{1800}{\cos 50^\circ}$
$P = 2800.3 \, \text{ N}$ answer