$s = 2t^4 - \frac{1}{6}t^3 + 2t^2$
$v = \dfrac{ds}{dt}$
$v = 8t^3 - \frac{1}{2}t^2 + 4t$
$a = \dfrac{dv}{dt}$
$a = 24t^2 - t + 4$
When t = 2 sec
$v = 8(2^3) - \frac{1}{2}(2^2) + 4(2)$
$v = 70 \, \text{ m/s}$ answer
$a = 24(2^2) - 2 + 4$
$a = 98\, \text{ m/s}^2$ answer