From the FBD of the whole system
$\Sigma M_E = 0$
$4R_D = 1.5(24)$
$R_D = 9 ~ \text{kN}$
From the FBD of Member AB
$\Sigma M_A = 0$
$3B_V = 2(24)$
$B_V = 16 ~ \text{kN}$
From the FBD of Member BD
$\Sigma F_V = 0$
$C_V + 9 = 16$
$C_V = 7 ~ \text{kN upward}$ answer
$\Sigma M_B = 0$
$1.5C_H = 1.5C_V + 3.5R_D$
$1.5C_H = 1.5(7) + 3.5(9)$
$C_H = 28 ~ \text{kN to the right}$ answer