For continuous flow
$Q_1 = Q_2 = Q_3 = Q$
$v_1A_1 = v_2A_2 = v_3A_3 = Q$
$v_1 [ \, \frac{1}{4}\pi (0.380^2) \, ] = v_2 [ \, \frac{1}{4}\pi (0.300^2) \, ] = v_3 [ \, \frac{1}{4}\pi (0.250^2) \, ] = 0.25$
$v_1 = \dfrac{4(0.25)}{\pi (0.380^2)} = 2.20 \, \text{ m/sec}$ answer
$v_2 = \dfrac{4(0.25)}{\pi (0.300^2)} = 3.54 \, \text{ m/sec}$ answer
$v_3 = \dfrac{4(0.25)}{\pi (0.250^2)} = 5.09 \, \text{ m/sec}$ answer