Contraction of steel rod, assuming complete freedom:



The steel rod cannot freely contract because of the resistance of aluminum rod. The movement of A (referred to as δA), therefore, is less than 0.4212 mm. In terms of aluminum, this movement is (by ratio and proportion):




![$ 0.4212 - \dfrac{P_{st} (900)}{300(200\,000)} = 0.5 \left[ \dfrac{P_{al} (1200)}{1\,200(70\,000)} \right] $](/files/tex/70ecafd2e91a2f02d4ed80a9db3db3d975497eed.png)
→ Equation (1)


→ Equation (2)
Equations (1) and (2)



answer