Problem 308 A 2-in-diameter steel shaft rotates at 240 rpm. If the shearing stress is limited to 12 ksi, determine the maximum horsepower that can be transmitted.
Solution 308
$12(1000) = \dfrac{16T}{\pi (2^3)}$
$T = 18\,849.56 \, \text{lb}\cdot\text{in}$
$T = \dfrac{P}{2\pi f}$
$18\,849.56 = \dfrac{P(396\,000)}{2\pi (240)}$ $P = 71.78 \, \text{ hp}$ answer
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