Solved Problem 07 | Rectangular Parallelepiped

$V_1 = 72 \, \text{ ft}^3$
 

$V_2 = 3(4)(2 \times 6)$

$V_2 = 144 \, \text{ ft}^3$
 

$\dfrac{V_2}{V_1} = \dfrac{144}{72}$

$V_2 = 2V_1$
 

The second is twice as large as the first.             answer