aluminum

Solution to Problem 275 Thermal Stress

275 Bar connected to two rods

Problem 275

A rigid horizontal bar of negligible mass is connected to two rods as shown in Fig. P-275. If the system is initially stress-free. Calculate the temperature change that will cause a tensile stress of 90 MPa in the brass rod. Assume that both rods are subjected to the change in temperature.

 

Solution to Problem 274 Thermal Stress

Problem 274

At what temperature will the aluminum and steel segments in Prob. 273 have numerically equal stress?

 

Solution 274

\sigma_{al} = \sigma_{st}
\dfrac{R_1}{2} = \dfrac{(50\,000 − R_1)}{3}
3R_1 = 100\,000 – 2R_1
R_1 = 20\,000 \, \text{lbs}

 

Free Body Diagram

 

Solution to Problem 273 Thermal Stress

273 Composite bar

Problem 273

The composite bar shown in Fig. P-273 is firmly attached to unyielding supports. An axial force P = 50 kips is applied at 60°F. Compute the stress in each material at 120°F. Assume α = 6.5 × 10–6 in/(in·°F) for steel and 12.8 × 10–6 in/(in·°F) for aluminum.

 

Solution to Problem 269 Thermal Stress

269 Copper and aluminum bars supporting a slab

Problem 269

As shown in Fig. P-269, there is a gap between the aluminum bar and the rigid slab that is supported by two copper bars. At 10°C, Δ = 0.18 mm. Neglecting the mass of the slab, calculate the stress in each rod when the temperature in the assembly is increased to 95°C. For each copper bar, A = 500 mm2, E = 120 GPa, and α = 16.8 µm/(m·°C). For the aluminum bar, A = 400 mm2, E = 70 GPa, and α = 23.1 µm/(m·°C).

Solution to Problem 268 Thermal Stress

268 Steel and aluminum rods

Problem 268

The rigid bar ABC in Fig. P-268 is pinned at B and attached to the two vertical rods. Initially, the bar is horizontal and the vertical rods are stress-free. Determine the stress in the aluminum rod if the temperature of the steel rod is decreased by 40°C. Neglect the weight of bar ABC.

Solution to Problem 257 Statically Indeterminate

257 Three bars and a strut

Problem 257

Three bars AB, AC, and AD are pinned together as shown in Fig. P-257. Initially, the assembly is stress free. Horizontal movement of the joint at A is prevented by a short horizontal strut AE. Calculate the stress in each bar and the force in the strut AE when the assembly is used to support the load W = 10 kips. For each steel bar, A = 0.3 in.2 and E = 29 × 106 psi. For the aluminum bar, A = 0.6 in.2 and E = 10 × 106 psi.

Solution to Problem 249 Statically Indeterminate

249 Aluminum tube placed inside steel tube

Problem 249

There is a radial clearance of 0.05 mm when a steel tube is placed over an aluminum tube. The inside diameter of the aluminum tube is 120 mm, and the wall thickness of each tube is 2.5 mm. Compute the contact pressure and tangential stress in each tube when the aluminum tube is subjected to an internal pressure of 5.0 MPa.

Solution to Problem 242 Statically Indeterminate

242 Bar and rods assembly

Problem 242

The assembly in Fig. P-242 consists of a light rigid bar AB, pinned at O, that is attached to the steel and aluminum rods. In the position shown, bar AB is horizontal and there is a gap, Δ = 5 mm, between the lower end of the steel rod and its pin support at C. Compute the stress in the aluminum rod when the lower end of the steel rod is attached to its support.

Solution to Problem 239 Statically Indeterminate

239 Block resting on three bars

Problem 239

The rigid platform in Fig. P-239 has negligible mass and rests on two steel bars, each 250.00 mm long. The center bar is aluminum and 249.90 mm long. Compute the stress in the aluminum bar after the center load P = 400 kN has been applied. For each steel bar, the area is 1200 mm2 and E = 200 GPa. For the aluminum bar, the area is 2400 mm2 and E = 70 GPa.

Solution to Problem 211 Axial Deformation

Strength of Materials 4th Edition by Pytel and Singer
Problem 211 page 40

Given:
Maximum overall deformation = 3.0 mm
Maximum allowable stress for steel = 140 MPa
Maximum allowable stress for bronze = 120 MPa
Maximum allowable stress for aluminum = 80 MPa
Est = 200 GPa
Eal = 70 GPa
Ebr = 83 GPa
The figure below:
Figure P-211

Required: The largest value of P

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