shear stress
Solution to Problem 316 Torsion
Problem 316
A compound shaft consisting of a steel segment and an aluminum segment is acted upon by two torques as shown in Fig. P-316. Determine the maximum permissible value of T subject to the following conditions: τst ≤ 83 MPa, τal ≤ 55 MPa, and the angle of rotation of the free end is limited to 6°. For steel, G = 83 GPa and for aluminum, G = 28 GPa.
- Add new comment
- Read more
- 40 reads
Solution to Problem 309 Torsion
Problem 309
A steel propeller shaft is to transmit 4.5 MW at 3 Hz without exceeding a shearing stress of 50 MPa or twisting through more than 1&dig; in a length of 26 diameters. Compute the proper diameter if G = 83 GPa.
- Add new comment
- Read more
- 45 reads
Solution to Problem 308 Torsion
Problem 308
A 2-in-diameter steel shaft rotates at 240 rpm. If the shearing stress is limited to 12 ksi, determine the maximum horsepower that can be transmitted.
- Add new comment
- Read more
- 44 reads
Solution to Problem 306 Torsion
Problem 306
A steel marine propeller shaft 14 in. in diameter and 18 ft long is used to transmit 5000 hp at 189 rpm. If G = 12 × 106 psi, determine the maximum shearing stress.
- Add new comment
- Read more
- 40 reads
Solution to Problem 305 Torsion
Problem 305
What is the minimum diameter of a solid steel shaft that will not twist through more than 3° in a 6-m length when subjected to a torque of 12 kN·m? What maximum shearing stress is developed? Use G = 83 GPa.
- Add new comment
- Read more
- 58 reads
Solution to Problem 240 Statically Indeterminate
Problem 240
Three steel eye-bars, each 4 in. by 1 in. in section, are to be assembled by driving rigid 7/8-in.-diameter drift pins through holes drilled in the ends of the bars. The center-line spacing between the holes is 30 ft in the two outer bars, but 0.045 in. shorter in the middle bar. Find the shearing stress developed in the drip pins. Neglect local deformation at the holes.
- Add new comment
- Read more
- 185 reads
Solution to Problem 131 Bearing Stress
Problem 131
Repeat Problem 130 if the rivet diameter is 22 mm and all other data remain unchanged.
- Read more
- 660 reads
Solution to Problem 130 Bearing Stress
Strength of Materials 4th Edition by Pytel and Singer
Problem 130 page 22
Given:
Allowable shear stress = 70 MPa
Allowable bearing stress = 140 MPa
Diameter of rivets = 19 mm
The truss below:

Required:
Number of rivets to fasten member BC to the gusset plate
Number of rivets to fasten member BE to the gusset plate
Largest average tensile or compressive stress in members BC and BE
- Read more
- 1120 reads
Solution to Problem 129 Bearing Stress
Strength of Materials 4th Edition by Pytel and Singer
Problem 129 page 21
Given:
Diameter of bolt = 7/8 inch
Diameter at the root of the thread (bolt) = 0.731 inch
Inside diameter of washer = 9/8 inch
Tensile stress in the nut = 18 ksi
Bearing stress = 800 psi
Required:
Shearing stress in the head of the bolt
Shearing stress in threads of the bolt
Outside diameter of the washer
- Read more
- 652 reads
Solution to Problem 128 Bearing Stress
Strength of Materials 4th Edition by Pytel and Singer
Problem 128 page 21
Given:
Shape of beam = W18 × 86
Shape of girder = W24 × 117
Shape of angles = 4 × 3-½ × 3/8
Diameter of rivets = 7/8 inch
Allowable shear stress = 15 ksi
Allowable bearing stress = 32 ksi
Required: Allowable load on the connection
- Read more
- 589 reads




