## Solution to Problem 126 Bearing Stress

- Read more about Solution to Problem 126 Bearing Stress
- Log in or register to post comments

## Solution to Problem 125 Bearing Stress

#### Problem 125

In Fig. 1-12, assume that a 20-mm-diameter rivet joins the plates that are each 110 mm wide. The allowable stresses are 120 MPa for bearing in the plate material and 60 MPa for shearing of rivet. Determine (a) the minimum thickness of each plate; and (b) the largest average tensile stress in the plates.

- Read more about Solution to Problem 125 Bearing Stress
- 1 comment
- Log in or register to post comments

## Solution to Problem 123 Shear Stress

**Problem 123**

A rectangular piece of wood, 50 mm by 100 mm in cross section, is used as a compression block shown in Fig. P-123. Determine the axial force P that can be safely applied to the block if the compressive stress in wood is limited to 20 MN/m^{2} and the shearing stress parallel to the grain is limited to 5MN/m^{2}. The grain makes an angle of 20° with the horizontal, as shown. (Hint: Use the results in Problem 122.)

- Read more about Solution to Problem 123 Shear Stress
- Log in or register to post comments

## Solution to Problem 122 Shear Stress

**Problem 122**

Two blocks of wood, width w and thickness t, are glued together along the joint inclined at the angle θ as shown in Fig. P-122. Using the free-body diagram concept in Fig. 1-4a, show that the shearing stress on the glued joint is τ = P sin 2θ / 2A, where A is the cross-sectional area.

- Read more about Solution to Problem 122 Shear Stress
- 1 comment
- Log in or register to post comments

## Solution to Problem 121 Shear Stress

**Problem 121**

Referring to Fig. P-121, compute the maximum force P that can be applied by the machine operator, if the shearing stress in the pin at B and the axial stress in the control rod at C are limited to 4000 psi and 5000 psi, respectively. The diameters are 0.25 inch for the pin, and 0.5 inch for the control rod. Assume single shear for the pin at B.

- Read more about Solution to Problem 121 Shear Stress
- Log in or register to post comments

## Solution to Problem 120 Shear Stress

**Problem 120**

The members of the structure in Fig. P-120 weigh 200 lb/ft. Determine the smallest diameter pin that can be used at A if the shearing stress is limited to 5000 psi. Assume single shear.

- Read more about Solution to Problem 120 Shear Stress
- 2 comments
- Log in or register to post comments

## Solution to Problem 119 Shear Stress

**Problem 119**

Compute the shearing stress in the pin at B for the member supported as shown in Fig. P-119. The pin diameter is 20 mm.

- Read more about Solution to Problem 119 Shear Stress
- Log in or register to post comments

## Solution to Problem 118 Shear Stress

**Problem 118**

A 200-mm-diameter pulley is prevented from rotating relative to 60-mm-diameter shaft by a 70-mm-long key, as shown in Fig. P-118. If a torque T = 2.2 kN·m is applied to the shaft, determine the width b if the allowable shearing stress in the key is 60 MPa.

- Read more about Solution to Problem 118 Shear Stress
- Log in or register to post comments

## Solution to Problem 117 Shear Stress

**Problem 117**

Find the smallest diameter bolt that can be used in the clevis shown in Fig. 1-11b if P = 400 kN. The shearing strength of the bolt is 300 MPa.

- Read more about Solution to Problem 117 Shear Stress
- 5 comments
- Log in or register to post comments

## Solution to Problem 116 Shear Stress

**Problem 116**

As in Fig. 1-11c, a hole is to be punched out of a plate having a shearing strength of 40 ksi. The compressive stress in the punch is limited to 50 ksi. (a) Compute the maximum thickness of plate in which a hole 2.5 inches in diameter can be punched. (b) If the plate is 0.25 inch thick, determine the diameter of the smallest hole that can be punched.

- Read more about Solution to Problem 116 Shear Stress
- Log in or register to post comments