A nutritionist in a hospital is arranging special diets that consist of a combination of three basic foods. It is important that the patients on this diet consume exactly 310 units of calcium, 190 units of iron, and 250 units of vitamin A each day. The amounts of these nutrients in one ounce food are given in the following table.
How many ounces each food must be used to satisfy the nutrient requirements exactly?
$10A + 10B + 20C = 190$ ← eq. (2)
$10A + 30B + 20C = 250$ ← eq. (3)
$A = 6$
$B = 3$
$C = 5$
Answer: [ C ]
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