# Compound Curves: Finding the Stationing of PCC with Given Stationing of PC

**Problems**

A compound curve has the following characteristics:

I_{1} = 24° |
D_{1} = 6° |

I_{2} = 36° |
D_{2} = 4° |

Stationing of P.C. = km 10 + 420 |

Compute the stationing of *P.C.C.*

A. km 10 + 560 | C. km 10 + 520 |

B. km 10 + 540 | D. km 10 + 500 |

**Answer Key**

[ D ]

**Solution**

$\dfrac{L_c}{I} = \dfrac{20}{D}$

$\dfrac{L_{c1}}{24^\circ} = \dfrac{20}{6^\circ}$

$L_{c1} = 80 ~ \text{m}$

$\begin{align}

\text{Sta.} ~ P.C.C & = \text{Sta.} ~ P.C. + \, L_{c1} \\

& = (10 + 420) + 80 \\

& = \text{km} ~ 10 + 500

\end{align}$

Answer: [ D ]

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