$\Sigma F_x = 0$

$F \cos 60^\circ + 300 = P \cos 15^\circ + 400 \cos 30^\circ$

$F = 1.9318P + 92.82$

$\Sigma F_y = 0$

$F \sin 60^\circ + P \sin 15^\circ = 200 + 400 \sin 30^\circ$

$(1.9318P + 92.82) \sin 60^\circ + P \sin 15^\circ = 200 + 400 \sin 30^\circ$

$1.6730P + 80.38 + 0.2588P = 200 + 200$

$1.9318P = 319.62$

$P = 165.45 \, \text{ lb}$ *answer*

$F = 1.9318(165.45) + 92.82$

$F = 412.44 \, \text{ lb}$ *answer*

Where did that 92.82 and 1.9318P came from?

evaluate the trigo functions and add/subtract like terms

Can you please give an example ?

bakit dinidisregard ung quadrants? hindi ba may negative/postive ung components depende kung saan sila nakapwesto?

Hindi actually yan dinisregard... siniparate lang sa solution ang upward sa downward at yung "to the left" fom "to the right".