z1= 4^(e^[(-i)(π/4)])

z2= -5i

z3= 3√3<30°

Note: < is the angle sign. I don't have symbol for.the angle sign in my keyboard.

Solve for:

[z1^(4cos z4)]/log(sub z1)z3

Please help :(

November 15, 2016 - 3:09am

#1
Advanced Engineering Mathematics: Solve for: [z1^(4cos z4)]/log(sub z1)z3

z1= 4^(e^[(-i)(π/4)])

z2= -5i

z3= 3√3<30°

Note: < is the angle sign. I don't have symbol for.the angle sign in my keyboard.

Solve for:

[z1^(4cos z4)]/log(sub z1)z3

Please help :(

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