# Differential Equation: $ye^{xy} dx + xe^{xy} dy = 0$

Submitted by qwerty on July 17, 2016 - 8:28am

Please help me to solve this differential equation

ye^{xy}dx+xe^{xy}dy=0

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Submitted by qwerty on July 17, 2016 - 8:28am

Please help me to solve this differential equation

ye^{xy}dx+xe^{xy}dy=0

- Log in to post comments
- 3675 reads

## $ye^{xy}\,dx + xe^{xy}\,dy =

$ye^{xy}\,dx + xe^{xy}\,dy = 0$

$e^{xy}(y\,dx + x\,dy) = 0$

$e^{xy} \, d(xy) = 0$

$\displaystyle \int e^{xy} \, d(xy) = 0$

$e^{xy} = c$

answer## Than you sir Romel. God bless

So it was not an exact equation haha. By the way thank you sir Romel. God bless.

## Boss pahelp naman po...

Boss pahelp naman po....pleassssssss sir.....

1. (2ycosx + sin⁴x)dx = sin x dy when x=½π, y=1

2. (1+4xy-4x²y) dx +(x²-x³)dy =0 when x=2, y=¼