( PASAGOT NAMAN PO ASSIGNMENT LANG PO HINDI KO TALAGA MASAGOT,, SALAMAT NG MARAMI.)An automobile is to travel a distance from A to B of 540m in exactly 4seconds. The auto accelerates and decelerates at 1.8 m/s^2, starting from rest A to rest B find velocity, maximum speed.

The maximum speed will occur exactly midway between A and B because it accelerate and decelerate at the same rate at 1.8 m/s^2.

Formula to use:

$v^2 = {v_o}^2 + 2as$

Solve for v at s = 540/2

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