$F_H = F(\frac{4}{5}) = 200(\frac{4}{5})$

$F_H = 160 \, \text{ kg}$

$F_V = F(\frac{3}{5}) = 200(\frac{3}{5})$

$F_V = 120 \, \text{ kg}$

$P_H = P(\frac{2}{\sqrt{13}}) = 165(\frac{2}{\sqrt{13}})$

$P_H = 91.526 \, \text{ kg}$

$P_V = P(\frac{3}{\sqrt{13}}) = 165(\frac{3}{\sqrt{13}})$

$P_V = 137.288 \, \text{ kg}$

**Moment of force F about points A, B, C, and D:**
$M_A = 5(0.3)F_V = 5(0.3)(120)$
$M_A = 180 \, \text{ kg}\cdot \text{m}$ → *answer*

$M_B = -6(0.3)F_H = -6(0.3)(160)$

$M_B = -288 \, \text{ kg}\cdot \text{m}$ → *answer*

$M_C = -0.3F_V - 3(0.3)F_H = -0.3(120) - 3(0.3)(160)$

$M_C = -180 \, \text{ kg}\cdot \text{m}$ → *answer*

$M_D = 5(0.3)F_V - 6(0.3)F_H = 5(0.3)(120) - 6(0.3)(160)$

$M_C = -108 \, \text{ kg}\cdot \text{m}$ → *answer*

**Moment of force P about points A, B, C, and D:**
$M_A = 6(0.3)P_H - 4(0.3)P_V = 6(0.3)(91.526) - 4(0.3)(137.288)$
$M_A = 0$ (this means that point A is on the line of action of force P) → *answer*

$M_B = 0.3P_V = 0.3(137.288)$

$M_B = 41.186 \, \text{ kg}\cdot \text{m}$ → *answer*

$M_C = 2(0.3)P_V + 3(0.3)P_H = 2(0.3)(137.288) + 3(0.3)(91.526)$

$M_C = 164.746 \, \text{ kg}\cdot \text{m}$ → *answer*

You can also resolve P to horizontal and vertical components at point E then take the moment of these components at point C. The answer would be the same. Try it.

$M_D = -4(0.3)P_V = -4(0.3)(137.288)$

$M_D = -164.746 \, \text{ kg}\cdot \text{m}$ → *answer*

Bkit mgkahiwalay ng kinonsider ung moment ng F at P sa point A, B, C and D? and ung Fv and Fh, Pv and Ph nasa dulo ng arrow? if kinonsider ko na nasa tail ng force siya mali na po ba siya?

The resolution of force into its components can be done anywhere within the line of action of the force. You can do it at the head, at the tail, or even at the extension points of your force.

Hello sir san po nakuha ung 5? Pag kukunin ang Moment ng f "5(0.3)(120)" pano po nangyari to? Tska ung directions niya po if counterclockwise or clockwise ba? Thanks

use ration and proportion or similar triangle.

d=sqrt((x^2)+(y^2))

d=sqrt((4^2)+((3^2))

d=5

san po nakuha ung 5 dun sa ma=5(0.3)120

at pano po naging -6 ung nsa baba nya

same question

Baliktad po yung mga signs ng mga moments, sabi po sa problem assume clockwise moments as positive