# Problem 007-cb | Analysis of Cabled Frame

**Problem 007-cb**

In the structure shown in Fig. CB-007(FR), members BCE, and CD are assumed to be solid rigid members. Members AE and DE are cables. For this structure, determine the

reaction at B.

**Solution 007-cb**

$\Sigma M_B = 0$

$24(\frac{2}{\sqrt{13}}T) = 12\,000(10 \sin 53^\circ)$

$T = 7198.80 \, \text{ lb}$

$\Sigma F_H = 0$

$B_H = \frac{2}{\sqrt{13}}T$

$B_H = \frac{2}{\sqrt{13}}(7198.81)$

$B_H = 3993.18 \, \text{ lb}$ *answer*

$\Sigma F_V = 0$

$B_V = \frac{3}{\sqrt{13}}T + 12\,000$

$B_V = 17 989.77 \, \text{ lb}$ *answer*