$\Sigma F_x = 0$
$F \cos 60^\circ + 300 = P \cos 15^\circ + 400 \cos 30^\circ$
$F = 1.9318P + 92.82$
$\Sigma F_y = 0$
$F \sin 60^\circ + P \sin 15^\circ = 200 + 400 \sin 30^\circ$
$(1.9318P + 92.82) \sin 60^\circ + P \sin 15^\circ = 200 + 400 \sin 30^\circ$
$1.6730P + 80.38 + 0.2588P = 200 + 200$
$1.9318P = 319.62$
$P = 165.45 \, \text{ lb}$ answer
$F = 1.9318(165.45) + 92.82$
$F = 412.44 \, \text{ lb}$ answer
Comments
how did you get the 92.82?
how did you get the 92.82?
by transposing the 300 to the
by transposing the 300 to the other side and divide it by cos(60)
Can you please show us how? I
Can you please show us how? I still can't figure it out