$\Sigma F_x = 0$

$F \cos 60^\circ + 300 = P \cos 15^\circ + 400 \cos 30^\circ$

$F = 1.9318P + 92.82$

$\Sigma F_y = 0$

$F \sin 60^\circ + P \sin 15^\circ = 200 + 400 \sin 30^\circ$

$(1.9318P + 92.82) \sin 60^\circ + P \sin 15^\circ = 200 + 400 \sin 30^\circ$

$1.6730P + 80.38 + 0.2588P = 200 + 200$

$1.9318P = 319.62$

$P = 165.45 \, \text{ lb}$ *answer*

$F = 1.9318(165.45) + 92.82$

$F = 412.44 \, \text{ lb}$ *answer*

## Comments

## how did you get the 92.82?

how did you get the 92.82?

## by transposing the 300 to the

by transposing the 300 to the other side and divide it by cos(60)

## Can you please show us how? I

Can you please show us how? I still can't figure it out

## How did you get the 1.9318P

How did you get the 1.9318P