Problem 332 Determine the reactions for the beam shown in Fig. P-332.

Solution 332

$10R_1 + 4(400) = 16(300) + 9[ \, 14(100) \, ]$

$R_1 = 1580 \, \text{ lb}$ answer

$\Sigma M_{R1} = 0$

$10R_2 + 6(300) = 14(400) + 1[ \, 14(100) \, ]$

$R_2 = 520 \, \text{ lb}$ answer

This is just a venial observation: Summation of M R1 should read 10R2 + 6(300) = 15(400) + 1[14(100)]

Nope. The distance between R1 and 400 lb is only 14 ft, not 15 ft.

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## Comments

## This is just a venial

This is just a venial observation: Summation of M R1 should read

10R2 + 6(300) = 15(400) + 1[14(100)]

## Nope. The distance between R1

Nope. The distance between R1 and 400 lb is only 14 ft, not 15 ft.