Problem 426 - Fink Truss by Method of Sections

Problem 426
Using the method of sections, compute the force in bars FH, GH, and EK.
 

426-fink-truss-given.gif

 

Solution 426

 
Infinitesimal
Infinitesimal's picture

Your solution to

$\sum M_E = 0$

You have $9F_{FH}+120+150+60=3F_{FH}+30+960$

Then It should be $6F_{FH}=660$ and not $3F_{FH}$ right?

Jhun Vert
Jhun Vert's picture

Yes po, tama ka, maraming salamat.

Infinitesimal
Infinitesimal's picture

So 110 kN na po yung sa unang member? hehe

Infinitesimal
Infinitesimal's picture

Also, yung 18 m po hehe

MATHalino
MATHalino's picture

The solution has been updated and also the figure. Thank you Infinitesimal sir.

Infinitesimal
Infinitesimal's picture

No problem, sir :)

reyjen_18

:)

Maricel Zamora
Maricel Zamora's picture

Bakit po ang x= z/cos 30?

hindi po ba dapat x= z cos30?

Jhun Vert
Jhun Vert's picture

In triangle ADE, x is hypotenuse.

Brandon Perez

Bakit po sa Sum of Moments @ E ay Ffh sin 30 lang yung ininclude di po kasama yung x(?) component ng Ffh?

Jhun Vert
Jhun Vert's picture

Nakuha na kasi ang perpendicular distance between FFH at point E which is 1/2 of x. Ang triangle CDE kasi ay equilateral.

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