Permalink Submitted by dodong on October 10, 2017 - 1:50pm.

where did the ratio 3/sqrt(34) come from? Shouldnt we be computing for the Y component of T (Ty) because all forces are vertical? If so, the angle at D is equal to tan < = 5/3 or 59.036 degrees. Ty should have been (cos 59.036 * T). The second part of the equation should have been 10(cos 59.036)*T which is not the same as 3/sqrt(3). Can someone explain how we derived the 3/sqrt(34) part. Thanks!

## Comments

## Small error in the figure but

Small error in the figure but still the answer is correct. :)

Sir, in the solution, the horizontal component of the green triangle is 5 and the vertical is 3.

## Thanks... Kailangan kung

Thanks... Kailangan kung kalkalin ang original file nito para magawan ng correction. naiflag ko na 'to for revision. Salamat uli.

## Why are the forces in members

Why are the forces in members AD and BD equal?

## smooth peg at D

## where did the ratio 3/sqrt(34

where did the ratio 3/sqrt(34) come from? Shouldnt we be computing for the Y component of T (Ty) because all forces are vertical? If so, the angle at D is equal to tan < = 5/3 or 59.036 degrees. Ty should have been (cos 59.036 * T). The second part of the equation should have been 10(cos 59.036)*T which is not the same as 3/sqrt(3). Can someone explain how we derived the 3/sqrt(34) part. Thanks!

## Pythagorean Theorem. Your

Pythagorean Theorem. Your cos 59.036 = 3/sqrt(34).

## napost kaya ung comment ko

thanks for the answer

## Paano po nangyari na 1/4 pi

Paano po nangyari na 1/4 pi (r)^2 yung area na ginamit sa cord? :) Salamat po sa sagot. :)

## Sorry. Ako po pala yung mali.

Sorry. Ako po pala yung mali. Diameter po pala yun. :)