Solution to Problem 107 Normal Stress

Problem 107
A rod is composed of an aluminum section rigidly attached between steel and bronze sections, as shown in Fig. P-107. Axial loads are applied at the positions indicated. If P = 3000 lb and the cross sectional area of the rod is 0.5 in2, determine the stress in each section.
 

107-composite-bar-two-forces_0.gif

 

Solution 107

 
Jal Rhee Ducusi...
Jal Rhee Ducusin Malugao's picture

Master. Bakit yung P sa bronze ay 9,000? Diba 3000 lang ang P ? O baka may na miss na point ako. Salamat po.

Jhun Vert
Jhun Vert's picture

The P you are going to use to solve for σ is the internal P of bronze, not the applied P = 3k. The internal P of each material is shown in the stress distribution diagram.

Quennie Lou Taw...
Quennie Lou Tawing Mondejar's picture

Sir bakit po ang 4P is equal to 12k sir? Maging ganito po ba sir 4P equal to Psteel ? since P equal to 3k so e substitute lang sir? At saka yung mga lengths sa baba e neglect lang yun sir? thank you po #BIGHELP

Jhun Vert
Jhun Vert's picture

Yes i-substitute lang and yes, neglect lang yung length.

Safdar Taunsvi
Safdar Taunsvi's picture

Sir tell me how p for bronze is 9 and how p are calculated

Jhun Vert
Jhun Vert's picture

Please refer to this reply.

JP Lariosa
JP Lariosa's picture

Sir paano po nakuha yong P12, 12 at 9 ?
Salamat po sir

Jhun Vert
Jhun Vert's picture

Pwede mong isa-isahin pagkuha ang mga internal P ng bawat material.

untitled_2.jpg
Mikko Selibio

Sir, paano naging equal ang 4P sa 12?

Jhun Vert
Jhun Vert's picture

P = 3 kips, hence, 4P = 12 kips.

Stone Temple Pilots

sir di ko ma gets pano naging 3P ang bronze? patulong po.

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