**Tensile force on the bolt:**
$P = \sigma A = 18 [ \, \frac{1}{4} \pi (\frac{7}{8})^2 \, ]$

$P = 10.82 \, \text{kips}$

**Shearing stress in the head of the bolt:**

$\tau = \dfrac{P}{A} = \dfrac{10.82}{\pi (\frac{7}{8})(\frac{1}{2})}$

$\tau = 7.872 \, \text{ ksi}$ *answer*

**Shearing stress in the threads:**

$\tau = \dfrac{P}{A} = \dfrac{10.82}{\pi (0.731)(\frac{5}{8})}$

$\tau = 7.538 \, \text{ ksi}$ *answer*

**Outside diameter of washer:**

$P = \sigma_b \, A_b$

$10.82(1000) = 800 \bigl\{ \, \frac{1}{4} \pi \, [ \, d^2 - (\frac{9}{8})^2 \, ] \, \bigr\}$

$d = 4.3 \, \text{inch}$ *answer*

## Comments

## Hello, why you are using "π d

Hello, why you are using "π d t" to find the Area? why not πd^2/4?

Thank You So Much :)

## Bakit po nakamultiply by 1000

Bakit po nakamultiply by 1000 yung 10.82kips? Hindi po ba dapat nakadivide?

## Okay na po pala. Haha.

Okay na po pala. Haha.