# Solution to Problem 226 Biaxial Deformation

Mohd Naseem Hashmi

Answer seems to be wrong. I think there is some typo here.
The answer should 2998.5 psi.
Since $$\frac{3430}{\pi}=2998.5$$
However we can get more accurate answer by considering the area of cross-section as $$A= \frac{\pi}{4}(d_2^2-d_1^2)$$
Where $$d_2$$is outside diameter and $$d_1$$ is inner diameter.

Jhun Vert

The formula for area used here is

$$A = \pi d t$$

Where d is supposed to be mean diameter and t is the thickness. We did not check the extent of the error. Sources of errors are (1) the formula itself is for very thin tube, (2) we use the inner diameter for d, instead of mean diameter.

Thank you for pointing it out.

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