Based on maximum allowable shearing stress:
$\tau_{max} = \dfrac{16TD}{\pi(D^4 - d^4)}$
$60 = \dfrac{16T(100)}{\pi (100^4 - 80^4)}$

$T = 6\,955 486.14 \, \text{N}\cdot\text{mm}$

$T = 6\,955.5 \, \text{N}\cdot\text{m}$

Based on maximum allowable angle of twist:

$\theta = \dfrac{TL}{JG}$
$0.5^\circ \left( \dfrac{\pi}{180^\circ} \right) = \dfrac{T(1000)}{\frac{1}{32}\pi (100^4 - 80^4)(83\,000)}$

$T = 4\,198\,282.97 \, \text{N}\cdot\text{mm}$

$T = 4\,198.28 \, \text{N}\cdot\text{m}$

Use the smaller torque, T = 4 198.28 N·m. *answer*

## Comments

## how find the value of L?? in

how find the value of L?? in the question I don't found the value of L?? but in solutions I see the value L-1000

## Hi there Ahsan! I think they

Hi there Ahsan! I think they used 1000 to make the imaginary "L" into a mm unit so that the equation is suitable to the formula. You're welcome in advance!

## The length is actually given

The length is actually given if you read it carefully. It is indicated in the maximum angle of twist which is 0.5 deg/m. That is for every 1 meter (or 1000 mm), you are limited to 0.5 deg rotation.

## Is there no need to convert 0

Is there no need to convert 0.5 deg/m to deg/mm ? ^^; i tried solving it on my own but noticed you didn't so i was wondering

## There is no need if your L =

There is no need if your L = 1000 mm in the right side of the equation, but if your L = 1 mm, then you should convert that that angle to deg/mm.

## Oh and uhh it says in the

Oh and uhh it says in the problem to <strong>Determine the maximmum torque</strong> but why do we choose the smaller one???

## It actually means the maximum

It actually means the maximum safe torque. If you load the larger larger torque, itwill resist the shear, but, it will twist beyond the allowable.