From the solution of

Problem 319:
Maximum T

_{br} = 4.970 kN·m

Maximum T

_{st} = 1.963 kN·m

$\theta_{br} = \theta_{st}$

$\left( \dfrac{TL}{JG} \right)_{br} = \left( \dfrac{TL}{JG} \right)_{st}$

$\dfrac{4.973a(1000^2)}{\frac{1}{32}\pi (75^4)(35\,000)} = \dfrac{1.963b (1000^2)}{\frac{1}{32}\pi (50^4)(83\,000)}$

$b/a = 1.187$

$T = T_{br \, max} + T_{st \, max}$

$T = 4.970 + 1.963$

$T = 6.933 \, \text{kN}\cdot\text{m}$ *answer*

## Comments

## san galing po yung squared sa

san galing po yung squared sa may 1000? LENGTH

## $T$ is in kN·m. kN to N ×1000

It is not from $L$, length gets cancelled from the equality. It is from $T$ which is in kN·m. Convert kN·m to N·mm. kN to N ×1000, and m to mm another ×1000.