Solution to Problem 562 | Unsymmetrical Beams

Problem 562
In any beam section having a maximum stress fb, show that the force on any partial area A' in Fig. P-562 is given by F = (fb/c)A'(barred y') , where (barred y') is the centroidal coordinate of A'. Also show that the moment of this force about the NA is M' = fb I'/c, where I' is the moment of inertia of the shaded area about the NA.

Beam of Any Section


Solution 562

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