Solution to Problem 625 | Moment Diagram by Parts

Problem 625
For the beam loaded as shown in Fig. P-625, compute the moment of area of the M diagrams between the reactions about both the left and the right reaction. (Hint: Draw the moment diagram by parts from right to left.)
 

Uniform load over 3/4 of span and concentrated load at midspan of simple beam

 

Solution 625

 
Mohd Naseem Hashmi
Mohd Naseem Hashmi's picture

The distance between the centroid of the second triangle i.e. the centroid of the area of the moment due to the load 500 N about $R_1$ and the support $R_2$ seems to be wrong.
Actually, it must be $4-\frac{2}{3}=\frac{10}{3}$.
So the answer would be 5750 $N\cdot m^3$ not $7750\, N\cdot m^3$.
Please correct it.

Jhun Vert
Jhun Vert's picture

Yes, it is obviously an error. Thank you for pointing it out.

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