Problem 7 The edges of the trunk are 3 ft., 4 ft., 6 ft. A second trunk is twice as long; the other edges are 3 ft., 4 ft. How do their volumes compare?

Solution 7

$V_1 = 72 \, \text{ ft}^3$

$V_2 = 3(4)(2 \times 6)$

$V_2 = 144 \, \text{ ft}^3$

$\dfrac{V_2}{V_1} = \dfrac{144}{72}$

$V_2 = 2V_1$

The second is twice as large as the first. answer

Follow @iMATHalino

MATHalino