# Problem 920 | Additional Centroidal Load to Eliminate Tensile Stress Anywhere Over the Cross Section

**Problem 920**

A compressive load *P* = 100 kN is applied, as shown in Fig. 9-8a, at a point 70 mm to the left and 30 mm above the centroid of a rectangular section for which *h* = 300 mm and *b* = 250 mm. What additional load, acting normal to the cross section at its centroid, will eliminate tensile stress anywhere over the cross section?

**Solution 920**

$\sigma_1 = 20/9 ~ \text{MPa}$

$f_{bx} = \dfrac{6M_x}{hb^2} = \dfrac{6(100,000 \times 30)}{300(150^2)}$

$f_{bx} = 8/3 ~ \text{MPa}$

$f_{by} = \dfrac{6M_y}{bh^2} = \dfrac{6(100,000 \times 70)}{150(300^2)}$

$f_{by} = 28/9 ~ \text{MPa}$

At corner *C*, both *f _{bx}* and

*f*are tensile stresses, hence, corner

_{by}*C*is carrying the largest tension

$\sigma_C = 32/9 ~ \text{MPa}$

Additional axial compression load *P*_{2} to eliminate tensile stress anywhere over the cross section.

$32/9 - \dfrac{P_2 (1000)}{300(150)} = 0$

$P_2 = 160 ~ \text{kN}$ ← *answer*