# Continuous Beams

## Continuous Beam With Equal Support Reactions

**Situation**

A beam 100 mm × 150 mm carrying a uniformly distributed load of 300 N/m rests on three supports spaced 3 m apart as shown below. The length *x* is so calculated in order that the reactions at all supports shall be the same.

1. Find *x* in meters.

A. 1.319 | C. 1.217 |

B. 1.139 | D. 1.127 |

2. Find the moment at *B* in N·m.

A. -240 | C. -242 |

B. -207 | D. -226 |

3. Calculate the reactions in Newton.

A. 843.4 | C. 863.8 |

B. 425.4 | D. 827.8 |

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## Continuous Beam With a Gap and a Zero Moment in Interior Support

**Situation**

A beam of uniform cross section whose flexural rigidity *EI* = 2.8 × 10^{11} N·mm^{2}, is placed on three supports as shown. Support *B* is at small gap Δ so that the moment at *B* is zero.

1. Calculate the reaction at *A*.

A. 4.375 kN | C. 5.437 kN |

B. 8.750 kN | D. 6.626 kN |

2. What is the reaction at *B*?

A. 4.375 kN | C. 5.437 kN |

B. 8.750 kN | D. 6.626 kN |

3. Find the value of Δ.

A. 46 mm | C. 34 mm |

B. 64 mm | D. 56 mm |

## Problem 885 | Continuous Beam by Moment Distribution Method

**Problem 885**

Solve for the support moments in Problem 825 if the ends are perfectly fixed instead of simply supported.

## Problem 879 | Continuous Beam by Moment Distribution Method

**Problem 879**

Using moment-distribution method, solve for the moments over supports R_{2} and R_{3} of the continuous beam in Figure P-827.

## Problem 878 | Continuous Beam by Moment Distribution Method

**Problem 878**

Using moment-distribution method, solve for the moments over supports R_{2} and R_{3} of the continuous beam in Figure P-826.