# English units

## Problem 18 - Bernoulli's Energy Theorem

**Problem 18**

Figure 4-09 shows a siphon discharging oil (sp gr 0.90). The siphon is composed of 3-in. pipe from A to B followed by 4-in. pipe from B to the open discharge at C. The head losses are from 1 to 2, 1.1 ft; from 2 to 3, 0.7 ft; from 3 to 4, 2.5 ft. Compute the discharge, and make table of heads at point 1, 2, 3, and 4.

## Problem 11 - Bernoulli's Energy Theorem

**Problem 11**

A horizontal pipe carries 30 cfs of water. At A the diameter is 18 in. and the pressure is 10 psi. At B the diameter is 36 in. and the pressure is 10.9 psi. Determine the head lost between the two points.

## Problem 06 - Bernoulli's Energy Theorem

**Problem 6**

As shown in Figure 4-03, the smaller pipe is cut off a short distance past the reducer so that the jet springs free into the air. Compute the pressure at 1 if Q = 5 cfs of water. D_{1} = 12 inches and D_{2} = 4 inches. Assume that the jet has the diameter D_{2}, that the pressure in the jet is atmospheric and that the loss of head from point 1 to point 2 is 5 ft of water.

## Problem 08 - Variation of Pressure

**Problem**

What is the pressure in pounds per square inch 4 ft below the surface of a liquid of sp. gr. 1.50 if the gas pressure on the surface is 0.4 atmosphere?

## Problem 06 - Variation of Pressure

**Problem**

If the pressure in the tank of oil (sp gr 0.80) is 60 psi, what is the equivalent head: (a) in feet of oil, (b) in feet of water, and (c) in inches of mercury?

## Problem 818 | Continuous Beam by Three-Moment Equation

**Problem 818**

In Problem 817, determine the changed value of the applied couple that will cause M_{2} to become zero.

## Problem 731 | Cantilever beam supported by cable at the free-end

**Problem 731**

The beam shown in Fig. P-731 is connected to a vertical rod. If the beam is horizontal at a certain temperature, determine the increase in stress in the rod if the temperature of the rod drops 90°F. Both the beam and the rod are made of steel with E = 29 × 10^{6} psi. For the beam, use I = 154 in.^{4}